How does one pass an init= option to the kernel? On the kernel line I placed init=3 Still the same problem on these two kernels kernel-3.11.8-300.fc20.x86_64 kernel-3.11.9-300.fc20.x86_64
tune2fs -c 1 is running just in case, can't fin any apparent problem with the hd, previous kernels boot fine.
Using the workarounds from: https://bugzilla.redhat.com/show_bug.cgi?id=905683
The problem box is a core2quad, 8gb ram
On 11/24/2013 02:20 AM, Frank Murphy wrote:
How does one pass an init= option to the kernel? On the kernel line I placed init=3 Still the same problem on these two kernels
init is process 1 on the booted system. Unless you have an executable named "3", this is not what you are looking for.
I suspect you want runlevel 3 which has nothing to do with the kernel. Just put "3" by itself on the kernel line and systemd will handle it. There's a name for that runlevel now as well but I don't know it off-hand.
On Sun, 2013-11-24 at 08:36 -0800, Samuel Sieb wrote:
On 11/24/2013 02:20 AM, Frank Murphy wrote:
How does one pass an init= option to the kernel? On the kernel line I placed init=3 Still the same problem on these two kernels
init is process 1 on the booted system. Unless you have an executable named "3", this is not what you are looking for.
I suspect you want runlevel 3 which has nothing to do with the kernel. Just put "3" by itself on the kernel line and systemd will handle it. There's a name for that runlevel now as well but I don't know it off-hand.
multi-user.target .