bash question

Il giorno mer, 31/10/2007 alle 09.28 -0400, Miner, Jonathan W (CSC) (US SSA) ha scritto: > By pipe'ing the commands together, you cause the while loop > to be executed in a subshell. Change your script to be: > > done << _EOF_ > a a a > b b b > c c c > _EOF_ > > echo $i > Thanks ... but my original script is someone like this: ls dir/| while read d do ... done then I have change it so: ls dir > /tmp/f.tmp while read d do .... done < /tmp/f.tmp rm -f /tmp/f.tmp Now all work fine! Thanks!!

Stupid bash tricks: while read d do .... done <<XX `ls dir/` XX Jeff Voskamp

Dario Lesca

9:07 a.m.

Il giorno mer, 31/10/2007 alle 14.58 +0100, Sjoerd Mullender ha scritto:

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Or: #!/bin/bash printf "a a a\nb b b\nc c c\n" | { i=0 while read x do i=$[i+1] echo "$x: ($i)" done echo $i }

Great! -- Dario Lesca <d.lesca(a)solinos.it>

Dario Lesca

8:36 a.m.

Il giorno mer, 31/10/2007 alle 09.28 -0400, Miner, Jonathan W (CSC) (US SSA) ha scritto:

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By pipe'ing the commands together, you cause the while loop to be executed in a subshell. Change your script to be: done << _EOF_ a a a b b b c c c _EOF_ echo $i

Thanks ... but my original script is someone like this: ls dir/| while read d do ... done then I have change it so: ls dir > /tmp/f.tmp while read d do .... done < /tmp/f.tmp rm -f /tmp/f.tmp Now all work fine! Thanks!! -- Dario Lesca <d.lesca(a)solinos.it>

Jacques B.

3:33 p.m.

On 10/31/07, Jacques B. <jjrboucher(a)gmail.com> wrote:

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On 10/31/07, Dario Lesca <d.lesca(a)solinos.it> wrote: > In this shell script: > > > #!/bin/bash > > i=0 > > > > printf "a a a\nb b b\nc c c\n" | > > while read x > > do > > i=$[i+1] > > echo "$x: ($i)" > > done > > > > echo $i > > with this output: > > > a a a: (1) > > b b b: (2) > > c c c: (3) > > 0 > > How to I can get the value (3) for $i out of the while loop? > > Many thanks > > -- > Dario Lesca <d.lesca(a)solinos.it> Is there a reason for using while instead of for? for x in $(ls dir/) do ..... done Jacques B.

The one caution when dealing with path/filenames is spaces. That was discussed not long ago and a few suggestions were given, mine being to change the $IFS variable but others were suggested that also worked if I recall. Jacques B.

Jacques B.

3:31 p.m.

On 10/31/07, Dario Lesca <d.lesca(a)solinos.it> wrote:

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In this shell script: > #!/bin/bash > i=0 > > printf "a a a\nb b b\nc c c\n" | > while read x > do > i=$[i+1] > echo "$x: ($i)" > done > > echo $i with this output: > a a a: (1) > b b b: (2) > c c c: (3) > 0 How to I can get the value (3) for $i out of the while loop? Many thanks -- Dario Lesca <d.lesca(a)solinos.it>

Is there a reason for using while instead of for? for x in $(ls dir/) do ..... done Jacques B.

Sjoerd Mullender

8:58 a.m.

Miner, Jonathan W (CSC) (US SSA) wrote:

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-----Original Message----- From: fedora-list-bounces(a)redhat.com on behalf of Dario Lesca Sent: Wed 10/31/2007 09:12 AM To: Fedora Project List Cc: Subject: bash question In this shell script: > #!/bin/bash > i=0 > > printf "a a a\nb b b\nc c c\n" | > while read x > do > i=$[i+1] > echo "$x: ($i)" > done > > echo $i ------------------------------- By pipe'ing the commands together, you cause the while loop to be executed in a subshell. Change your script to be: #!/bin/bash i=0 while read x do i=$[i+1] echo "$x: ($i)" done << _EOF_ a a a b b b c c c _EOF_ echo $i

Or: #!/bin/bash printf "a a a\nb b b\nc c c\n" | { i=0 while read x do i=$[i+1] echo "$x: ($i)" done echo $i } -- Sjoerd Mullender

Miner, Jonathan W (US SSA)

8:28 a.m.

-----Original Message----- From: fedora-list-bounces(a)redhat.com on behalf of Dario Lesca Sent: Wed 10/31/2007 09:12 AM To: Fedora Project List Cc: Subject: bash question In this shell script:

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#!/bin/bash i=0 printf "a a a\nb b b\nc c c\n" | while read x do i=$[i+1] echo "$x: ($i)" done echo $i

------------------------------- By pipe'ing the commands together, you cause the while loop to be executed in a subshell. Change your script to be: #!/bin/bash i=0 while read x do i=$[i+1] echo "$x: ($i)" done << _EOF_ a a a b b b c c c _EOF_ echo $i

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participants (5)

Dario Lesca
Jacques B.
Jeff Voskamp
Miner, Jonathan W (US SSA)
Sjoerd Mullender